Problem: Consider the following precipitation reaction: 2 Na3PO4(aq) + 3 CuCl2(aq) → Cu3(PO4)2(s) + 6 NaCl(aq) ;{ m{Cu}}_3 ({ m{PO}}_4 )_2 (s); + ;6;{ m{NaCl}}(aq)What volume of 0.176 M Na3PO4 solution is necessary to completely react with 90.5 mL of 0.113 M CuCl2?

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We will begin solving this problem by analyzing what information we have, to solve this problem:

             2 Na3PO4(aq) + 3 CuCl2(aq) → Cu3(PO4)2(s) + 6 NaCl(aq)

Concentration         0.176M                       0.113M

Volume                     mL = ?                       90.5mL

To be calculated      moles = ?                  moles = ?      

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Problem Details

Consider the following precipitation reaction: 2 Na3PO4(aq) + 3 CuCl2(aq) → Cu3(PO4)2(s) + 6 NaCl(aq)

What volume of 0.176 M Na3PO4 solution is necessary to completely react with 90.5 mL of 0.113 M CuCl2?

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