We’re being asked to calculate the **mass of CaCl _{2} (in g)** needed to make 6.0 L of a 0.310 M CaCl

Recall that ** molarity** is the ratio of the moles of solute and the volume of solution (in liters).

In other words:

$\overline{){\mathbf{Molarity}}{\mathbf{\left(}}{\mathbf{M}}{\mathbf{\right)}}{\mathbf{=}}\frac{\mathbf{moles}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solute}}{\mathbf{Liters}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solution}}}$

A chemist wants to make 6.0 L of a 0.310 M CaCl_{2} solution.

What mass of CaCl_{2} (in g) should the chemist use?

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