We’re being asked to calculate the mass of NaNO3 in 410.0 mL of a 1.2 M NaNO3 solution.
To do so, we shall do these steps:
Step 1: Calculate the moles of NaNO3.
Step 2: Calculate the mass of NaNO3.
Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters).
In other words:
A laboratory procedure calls for making 410.0 mL of a 1.2 M NaNO3 solution.
What mass of NaNO3 (in g) is needed?
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What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Molarity concept. You can view video lessons to learn Molarity. Or if you need more Molarity practice, you can also practice Molarity practice problems.