Chemistry Molarity Solution: A laboratory procedure calls for making 410.0 mL o...

Solution: A laboratory procedure calls for making 410.0 mL of a 1.2 M NaNO3 solution.What mass of NaNO3 (in g) is needed?

Problem

A laboratory procedure calls for making 410.0 mL of a 1.2 M NaNO3 solution.

What mass of NaNO3 (in g) is needed?

Solution

We’re being asked to calculate the mass of NaNO3 in 410.0 mL of a 1.2 M NaNO3 solution.


To do so, we shall do these steps:

Step 1: Calculate the moles of NaNO3

Step 2: Calculate the mass of NaNO3.


Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters)

In other words:


Molarity(M)=moles of soluteLiters of solution


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