A laboratory procedure calls for making 410.0 mL of a 1.2 M NaNO3 solution.
What mass of NaNO3 (in g) is needed?
We’re being asked to calculate the mass of NaNO3 in 410.0 mL of a 1.2 M NaNO3 solution.
To do so, we shall do these steps:
Step 1: Calculate the moles of NaNO3.
Step 2: Calculate the mass of NaNO3.
Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters).
In other words: