We’re being asked to calculate the **molarity (M****)**** of NO _{3}**

$\overline{){\mathbf{Molarity}}{\mathbf{}}{\mathbf{\left(}}{\mathbf{M}}{\mathbf{\right)}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{moles}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solute}}{\mathbf{Liter}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solution}}}$

We shall do the following:

What is the molarity of NO_{3}^{-} in each solution?

0.260 M Ca(NO_{3})_{2}.