$\overline{)\mathbf{Molarity}\mathbf{}\mathbf{=}\frac{\mathbf{moles}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solute}}{\mathbf{Liters}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solution}}}$

Calculate the molarity of each of the following solutions.

4.25 mol of LiCl in 2.90 L solution

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