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Problem: Urea (CH4N2O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH3) with carbon dioxide as follows: 2NH3(aq) + CO2(aq) → CH4N2O(aq) + H2O(l). In an industrial synthesis of urea, a chemist combines 133.0 kg of ammonia with 211.4 kg of carbon dioxide and obtains 173.0 kg of urea.Determine the percent yield for the reaction.

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2NH3(aq) + CO2(aq) → CH4N2O(aq) + H2O(l)


211.4 kg CO2 ×1 mol CO244.01×10-3 kg CO2×1 mol CH4N2O1 mol CO2×60.062×10-3 kg CH4N2O1 mol CH4N2O

= 289 g urea → excess

133.0 kg NH3 ×1 mol NH317.034×10-3 kg NH3×1 mol CH4N2O2 mol NH3×60.062×10-3 kg CH4N2O1 mol CH4N2O

= 234 g urea → limiting


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Problem Details

Urea (CH4N2O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH3) with carbon dioxide as follows: 2NH3(aq) + CO2(aq) → CH4N2O(aq) + H2O(l). In an industrial synthesis of urea, a chemist combines 133.0 kg of ammonia with 211.4 kg of carbon dioxide and obtains 173.0 kg of urea.

Determine the percent yield for the reaction.

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