Problem: Lead ions can be precipitated from solution with KCl according to the following reaction: Pb2+ (aq) + 2 KCl (aq) → PbCl2 (s) + 2 K+ (aq)When 28.6 g KCl is added to a solution containing 25.7 g Pb2+, a PbCl2 precipitate forms. The precipitate is filtered and dried and found to have a mass of 29.4 .  The theoretical yield is 34.5 g PbCl2.  Determine the percent yield for the reaction.

FREE Expert Solution
95% (344 ratings)
FREE Expert Solution

Recall that percent yield is given by:


%Yield=actual yieldtheoretical yield×100


95% (344 ratings)
Problem Details

Lead ions can be precipitated from solution with KCl according to the following reaction: 

Pb2+ (aq) + 2 KCl (aq) → PbCl2 (s) + 2 K+ (aq)

When 28.6 g KCl is added to a solution containing 25.7 g Pb2+, a PbCl2 precipitate forms. The precipitate is filtered and dried and found to have a mass of 29.4 .  The theoretical yield is 34.5 g PbCl2.  Determine the percent yield for the reaction.

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