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Problem: For the reaction shown, compute the theoretical yield of product (in grams) for each of the following initial amounts of reactants.2Al(s) + 3Cl2(g) → 2AlCl3(s)2.5 g Al, 2.5 g Cl2

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2 Al(s) + 3 Cl2(g) → 2 AlCl3(s)

Calculate the amount of AlCl3 produced from each reactant and determine the limiting reactant:

mass Al (molar mass) → moles Al(mole-to-mole comparison) → moles AlCl3(molar mass) → mass AlCl3

molar mass Al = 26.982 g/mol
molar mass AlCl3 = 133.332 g/mol

mass AlCl3=2.5 g Al×1 mol Al26.982 g Al×2 mol AlCl32 mol Al×133.332 g AlCl31 mol AlCl3

mass AlCl3 = 12.35 g


mass Cl2 (molar mass) → moles Cl2 (mole-to-mole comparison) → moles AlCl3 (molar mass) → mass AlCl3

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Problem Details

For the reaction shown, compute the theoretical yield of product (in grams) for each of the following initial amounts of reactants.
2Al(s) + 3Cl2(g) → 2AlCl3(s)

2.5 g Al, 2.5 g Cl2

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.