1 mol Mn = 1 mol MnO2
For the reaction
Mn(s) + O2(g) → MnO2(s)compute the theoretical yield of product (in moles) for each of the following initial amounts of reactants.
You may want to reference (Pages 146 - 151) Section 4.3 while completing this problem.
28.0 mol Mn and 44.0 mol O2
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