Problem: For the reaction shown, compute the theoretical yield of the product (in moles) for each of the following initial amounts of reactants.Ti(s) + 2Cl2(g) → TiCl4(s)12.6 mol Ti, 18.8 mol Cl2

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Ti(s) + 2Cl2(g) → TiCl4(s)

Calculate the amount of TiCl4 produced from each reactant and determine the limiting reactant:

moles Ti (mole-to-mole comparison) → moles TiCl4

moles TiCl4=12.6 moles Ti×1 mol TiF41 mol Ti

moles TiCl4 = 12.6 mol


moles Cl2 (mole-to-mole comparison) → moles TiCl4

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Problem Details

For the reaction shown, compute the theoretical yield of the product (in moles) for each of the following initial amounts of reactants.
Ti(s) + 2Cl2(g) → TiCl4(s)

12.6 mol Ti, 18.8 mol Cl2

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