H_{2}SO_{4} (aq) + 2 KOH(aq) → 2 H_{2}O(l) + K_{2}SO_{4}(aq)

base → KOH

acid → H_{2}SO_{4}

mass KOH (molar mass) → moles KOH (mole-to-mole comparison) → moles H_{2}SO_{4} (molar mass) → mass H_{2}SO_{4}

molar mass KOH = 56.11 g/mol

For each of the following acid-base reactions, calculate the mass (in grams) of each acid necessary to completely react with and neutralize 4.70 g of the base.

H_{2}SO_{4} (aq) + 2 KOH(aq) → 2 H_{2}O(l) + K_{2}SO_{4}(aq)

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