Step 1. Determine the %C, %H, and %O.
9.32 g C
1.57 g H
%O = 100 - (31.57 + 5.32) = 63.11%
Step 2. Determine mol C, H, and O.
Assume 100 g sample, therefore we have 31.57 g C, 5.32g H, and 63.11 g O.
2.63 mol C
5.28 mol H
3.94 mol O
Step 3. Determine the empirical formula.
Combustion of 29.52 g of a compound containing only carbon, hydrogen, and oxygen produces 34.17 g CO2 and 13.99 g H2O. What is the empirical formula of the compound?
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