Ch.3 - Chemical ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: A mixture of NaCl and NaBr has a mass of 2.05 g and is found to contain 0.75 g of Na.What is the mass of NaBr in the mixture?

Solution: A mixture of NaCl and NaBr has a mass of 2.05 g and is found to contain 0.75 g of Na.What is the mass of NaBr in the mixture?

Problem

A mixture of NaCl and NaBr has a mass of 2.05 g and is found to contain 0.75 g of Na.

What is the mass of NaBr in the mixture?

Solution

This is a problem where, we have two unknowns.


The mass of Na that is found in the sample comes from both the mass of NaCl and mass of NaBr.


To solve this problem, we will need molar masses of NaCl and NaBr.


Molar mass of NaCl


<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>N</mi><mi>a</mi><mi>C</mi><mi>l</mi><mspace linebreak="newline"></mspace><mi>N</mi><mi>a</mi><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>1</mn><mo>&#xD7;</mo><mn>22</mn><mo>.</mo><mn>99</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>22</mn><mo>.</mo><mn>99</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mspace linebreak="newline"></mspace><mi>C</mi><mi>l</mi><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>1</mn><mo>&#xD7;</mo><mn>35</mn><mo>.</mo><mn>45</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>35</mn><mo>.</mo><mn>45</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mspace linebreak="newline"></mspace><menclose mathcolor="#FF0000" notation="box"><mi>N</mi><mi>a</mi><mi>C</mi><mi>l</mi><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>58</mn><mo>.</mo><mn>44</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac></menclose></math>


Molar mass of NaBr


<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>N</mi><mi>a</mi><mi>B</mi><mi>r</mi><mspace linebreak="newline"></mspace><mi>N</mi><mi>a</mi><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>1</mn><mo>&#xD7;</mo><mn>22</mn><mo>.</mo><mn>99</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>22</mn><mo>.</mo><mn>99</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mspace linebreak="newline"></mspace><mi>B</mi><mi>r</mi><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>1</mn><mo>&#xD7;</mo><mn>79</mn><mo>.</mo><mn>90</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>79</mn><mo>.</mo><mn>90</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac><mspace linebreak="newline"></mspace><menclose mathcolor="#FF0000" notation="box"><mi>N</mi><mi>a</mi><mi>B</mi><mi>r</mi><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><mn>102</mn><mo>.</mo><mn>89</mn><mo>&#xA0;</mo><mfrac bevelled="true"><mi>g</mi><mrow><mi>m</mi><mi>o</mi><mi>l</mi></mrow></mfrac></menclose></math>


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