Problem: Combustion analysis of a 13.42-g sample of equilin (which contains only carbon, hydrogen, and oxygen) produced 39.61 g CO2 and 9.01 g H2 O. The molar mass of equilin is 268.34 g/mol .Find the molecular formula for equilin.

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FREE Expert Solution

We have to determine the molecular formula of equilin, 13.42 g of which produce 39.61 g CO2 and 9.01 g H2O upon combustion.


Molecular formula is a chemical formula that gives the actual number of atoms of elements in a compound.


We will calculate the empirical formula through these steps:

Step 1: Find the mass of C and H using the given masses of CO2 and H2O.

Step 2: Find the percentage of C, H and O in the compound.

Step 3: Dividing the percentages of C, H and O by their average atomic masses.

Step 4: Dividing the obtained numbers by the smallest number among them and rounding off to the nearest whole numbers to get the empirical formula.

Step 5: Calculate molecular formula of the compound.


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Problem Details

Combustion analysis of a 13.42-g sample of equilin (which contains only carbon, hydrogen, and oxygen) produced 39.61 g CO2 and 9.01 g H2 O. The molar mass of equilin is 268.34 g/mol .

Find the molecular formula for equilin.

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Empirical Formula concept. You can view video lessons to learn Empirical Formula. Or if you need more Empirical Formula practice, you can also practice Empirical Formula practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor des Georges' class at CCNY.