# Problem: Combustion analysis of a 13.42-g sample of equilin (which contains only carbon, hydrogen, and oxygen) produced 39.61 g CO2 and 9.01 g H2 O. The molar mass of equilin is 268.34 g/mol .Find the molecular formula for equilin.

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###### FREE Expert Solution

We have to determine the molecular formula of equilin, 13.42 g of which produce 39.61 g CO2 and 9.01 g H2O upon combustion.

Molecular formula is a chemical formula that gives the actual number of atoms of elements in a compound.

We will calculate the empirical formula through these steps:

Step 1: Find the mass of C and H using the given masses of CO2 and H2O.

Step 2: Find the percentage of C, H and O in the compound.

Step 3: Dividing the percentages of C, H and O by their average atomic masses.

Step 4: Dividing the obtained numbers by the smallest number among them and rounding off to the nearest whole numbers to get the empirical formula.

Step 5: Calculate molecular formula of the compound. ###### Problem Details

Combustion analysis of a 13.42-g sample of equilin (which contains only carbon, hydrogen, and oxygen) produced 39.61 g CO2 and 9.01 g H2 O. The molar mass of equilin is 268.34 g/mol .

Find the molecular formula for equilin.