$\overline{)\mathbf{mass}\mathbf{}\mathbf{percent}\mathbf{=}\frac{\mathbf{mass}\mathbf{}\mathbf{element}}{\mathbf{total}\mathbf{}\mathbf{mass}\mathbf{}\mathbf{of}\mathbf{}\mathbf{compound}}\mathbf{\times}\mathbf{100}}$

sulfurous acid:

sulfur**ous** → change "-ous to "-ite" → sulfite ion → SO_{3}^{2-}

acid → add H^{+}

2 H^{+} + SO_{3}^{2-} → H_{2}SO_{3}

sulfurous acid:** H _{2}SO**

molar mass H = 1.01 g/mol

molar mass S = 32.06 g/mol

molar mass O = 16.00 g/mol

molar mass H_{2}SO_{3} = (1.01 g/mol x 2) + 32.06 g/mol + (16.00 g/mol x 3)

**molar mass H_{2}SO_{3} = 82.08 g/mol**

**Mass percent of H:**

total mass H = 1.01 g/mol x 2

**total mass H = 2.02 g/mol**

Determine the chemical formula of each of the following compounds and then use it to calculate the mass percent composition of each constituent element.

sulfurous acid

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