We have to calculate the empirical formula of phosphorous selenide using the given masses of elements.
The given masses are: Phosphorous = 44.4 mg and compound = 129 mg
Empirical formula is a chemical formula that gives the relative proportions of elements in a compound but not the actual number of atoms of elements in a compound.
Empirical formula of a compound can be calculated using these steps:
Step 1: Find the masses of elements in the compound.
Step 2: Find the percentages elements in the compound.
Step 3: Dividing the percentages of elements by their average atomic masses.
Step 4: Dividing the obtained numbers by the smallest number among them and rounding off to the nearest whole numbers to get the empirical formula.
A 44.4 mg sample of phosphorus reacts with selenium to form 129 mg of the compound.
What is the empirical formula of the phosphorus selenide?
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