Problem: A 44.4 mg sample of phosphorus reacts with selenium to form 129 mg of the compound.What is the empirical formula of the phosphorus selenide?

FREE Expert Solution

We have to calculate the empirical formula of phosphorous selenide using the given masses of elements.


The given masses are: Phosphorous = 44.4 mg and compound = 129 mg


Empirical formula is a chemical formula that gives the relative proportions of elements in a compound but not the actual number of atoms of elements in a compound.


Empirical formula of a compound can be calculated using these steps:

Step 1: Find the masses of elements in the compound.

Step 2: Find the percentages elements in the compound.

Step 3: Dividing the percentages of elements by their average atomic masses.

Step 4: Dividing the obtained numbers by the smallest number among them and rounding off to the nearest whole numbers to get the empirical formula.

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Problem Details

A 44.4 mg sample of phosphorus reacts with selenium to form 129 mg of the compound.

What is the empirical formula of the phosphorus selenide?

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What scientific concept do you need to know in order to solve this problem?

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