# Problem: A 44.4 mg sample of phosphorus reacts with selenium to form 129 mg of the compound.What is the empirical formula of the phosphorus selenide?

###### FREE Expert Solution

We have to calculate the empirical formula of phosphorous selenide using the given masses of elements.

The given masses are: Phosphorous = 44.4 mg and compound = 129 mg

Empirical formula is a chemical formula that gives the relative proportions of elements in a compound but not the actual number of atoms of elements in a compound.

Empirical formula of a compound can be calculated using these steps:

Step 1: Find the masses of elements in the compound.

Step 2: Find the percentages elements in the compound.

Step 3: Dividing the percentages of elements by their average atomic masses.

Step 4: Dividing the obtained numbers by the smallest number among them and rounding off to the nearest whole numbers to get the empirical formula. ###### Problem Details

A 44.4 mg sample of phosphorus reacts with selenium to form 129 mg of the compound.

What is the empirical formula of the phosphorus selenide?