Ch.11 - Liquids, Solids & Intermolecular ForcesWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: For each of the following pairs of molecules, identify the dominate intermolecular force, and answer the associated question.a. NH2CH2CH2CH3            N(CH 3)3____________________   _________________

Problem

For each of the following pairs of molecules, identify the dominate intermolecular force, and answer the associated question.

a. NH2CH2CH2CH3            N(CH 3)3

____________________   ____________________

Which of the above compounds is expected to have the highest viscosity?

 

b. CsF                                 ClF

____________________   ____________________

Which of the above compounds is expected to have the highest vapor pressure?

 

c. CO2                                SO   2

____________________  ____________________

Which of the above compounds is expected to have the highest boiling point?

 

When we looked at the series of compounds: H 2O, H2S, H2Se, H2Te, boiling point increased from H2S to H2Se to H2Te, but H2O had the highest boiling point of the four. Explain the trend and why H2O is an exception.

  

 

If, however, you look at the trend for the compounds: (H 3C)2O, (H3C)2S, (H3C)2Se, (H3C)2Te, then boiling point increases as you go down the periodic table and (H3C)2O is not an exception. Explain.