Ch.11 - Liquids, Solids & Intermolecular ForcesWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Titanium tetrachloride, TiCl4, has a melting point of −23.2 °C and has a ΔHfusion = 9.37 kJ/mol.(a) How much energy is required to melt 263.1 g TiCl4?

Solution: Titanium tetrachloride, TiCl4, has a melting point of −23.2 °C and has a ΔHfusion = 9.37 kJ/mol.(a) How much energy is required to melt 263.1 g TiCl4?

Problem

Titanium tetrachloride, TiCl4, has a melting point of −23.2 °C and has a ΔHfusion = 9.37 kJ/mol.

(a) How much energy is required to melt 263.1 g TiCl4?

Solution

The problem did not specify the initial temperature of Titanium tetrachloride, TiCl4 nor we are given the specific heat. In this case, we'll assume that TiClis already at melting temperature and we will only be concerned with the Latent heat which is the heat needed for phase change.  ΔHfusion is given in KJ/mol so the formula we'll use is given below: 

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