Problem: How much heat is required to convert 422 g of liquid H2O at 23.5 °C into steam at 150 °C?

FREE Expert Solution

The amount of energy (q) needed to freeze a given mass is calculated using:


q=n×ΔHvaporization


where:

n = number of moles

ΔHvaporization = heat of vaporization (in J/mol)



We’re given:

m = 422  g

ΔHvaporization = 40.65 kJ/mol


Since we are given the mass of liquid water, we need to determine the number of moles of water.


The molar mass of H2O is 18.016 g/mol.


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How much heat is required to convert 422 g of liquid H2O at 23.5 °C into steam at 150 °C?

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