# Problem: How much heat is required to convert 422 g of liquid H2O at 23.5 °C into steam at 150 °C?

###### FREE Expert Solution

The amount of energy (q) needed to freeze a given mass is calculated using:

$\overline{){\mathbf{q}}{\mathbf{=}}{\mathbf{n}}{\mathbf{×}}{{\mathbf{\Delta H}}}_{{\mathbf{vaporization}}}}$

where:

n = number of moles

ΔHvaporization = heat of vaporization (in J/mol)

We’re given:

m = 422  g

ΔHvaporization = 40.65 kJ/mol

Since we are given the mass of liquid water, we need to determine the number of moles of water.

The molar mass of H2O is 18.016 g/mol.

97% (7 ratings) ###### Problem Details

How much heat is required to convert 422 g of liquid H2O at 23.5 °C into steam at 150 °C?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Heating and Cooling Curves concept. You can view video lessons to learn Heating and Cooling Curves. Or if you need more Heating and Cooling Curves practice, you can also practice Heating and Cooling Curves practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Woolman's class at MSCD.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry - OpenStax 2015th Edition. You can also practice Chemistry - OpenStax 2015th Edition practice problems.