Problem: How much heat is required to convert 422 g of liquid H2O at 23.5 °C into steam at 150 °C?

🤓 Based on our data, we think this question is relevant for Professor Woolman's class at MSCD.

FREE Expert Solution

The amount of energy (q) needed to freeze a given mass is calculated using:

$\overline{){\mathbf{q}}{\mathbf{=}}{\mathbf{n}}{\mathbf{×}}{{\mathbf{\Delta H}}}_{{\mathbf{vaporization}}}}$

where:

n = number of moles

ΔHvaporization = heat of vaporization (in J/mol)

We’re given:

m = 422  g

ΔHvaporization = 40.65 kJ/mol

Since we are given the mass of liquid water, we need to determine the number of moles of water.

The molar mass of H2O is 18.016 g/mol.

Problem Details

How much heat is required to convert 422 g of liquid H2O at 23.5 °C into steam at 150 °C?