Recall that the solubility of a gas is given by ** Henry’s law**:

$\overline{){{\mathbf{S}}}_{{\mathbf{gas}}}{\mathbf{=}}{{\mathbf{k}}}_{{\mathbf{H}}}{\mathbf{\xb7}}{{\mathbf{P}}}_{{\mathbf{gas}}}}$

$\overline{){\mathbf{Molarity}}{\mathbf{}}{\mathbf{\left(}}{\mathbf{M}}{\mathbf{\right)}}{\mathbf{=}}\frac{\mathbf{moles}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solute}}{\mathbf{Liters}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solution}\mathbf{}}}$

Molar mass of C_{2}H_{2}Cl_{2 }= 96.94 g/mol

${\mathbf{S}}_{{\mathbf{C}}_{\mathbf{2}}{\mathbf{H}}_{\mathbf{2}}{\mathbf{Cl}}_{\mathbf{2}}}\mathbf{=}\frac{\mathbf{0}\mathbf{.}\mathbf{65}\mathbf{}\overline{)\mathbf{mg}}}{\mathbf{1}\mathbf{}\mathbf{L}}\mathbf{\times}\frac{{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\overline{)\mathbf{g}}}{\mathbf{1}\mathbf{}\overline{)\mathbf{mg}}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\mathbf{mol}\mathbf{}{\mathbf{C}}_{\mathbf{2}}{\mathbf{H}}_{\mathbf{2}}{\mathbf{Cl}}_{\mathbf{2}}}{\mathbf{}\mathbf{96}\mathbf{.}\mathbf{94}\mathbf{}\overline{)\mathbf{g}\mathbf{}{\mathbf{C}}_{\mathbf{2}}{\mathbf{H}}_{\mathbf{2}}{\mathbf{Cl}}_{\mathbf{2}}}}$

${\mathbf{S}}_{{\mathbf{C}}_{\mathbf{2}}{\mathbf{H}}_{\mathbf{2}}{\mathbf{Cl}}_{\mathbf{2}}}\mathbf{=}$**6.705 x 10 ^{-6 }mol/ L**

A river is contaminated with 0.65 mg/L of dichloroethylene (C_{2}H_{2}Cl_{2}). What is the concentration (in ng/L) of dichloroethylene at 21°C in the air breathed by a person swimming in the river (k_{H} for C_{2}H_{2}Cl_{2} in water is 0.033 mol/L·atm)?

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