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An aqueous solution is 10.% glucose by mass (d = 1.039 g/mL at 20°C). Calculate its freezing point, boiling point at 1 atm, and osmotic pressure.

The mass percent of a solution is given by:

In a 10% by mass glucose (C_{6}H_{12}O_{6}) solution, this means there are **10 g of glucose for every 100 g solution**. From this, we can calculate the mass of water (the solvent):

We need to find the molality of the solution since we'll use it to calculate the freezing point depression and boiling point elevation. Recall that molality is:

The molar mass of glucose is 6(12.01 g/mol C) + 12(1.01 g/mol H) + 6(16.00 g/mol O) = **180.18 g/mol**. Calculating the molality of the glucose solution:

Freezing Point Depression

Freezing Point Depression

Freezing Point Depression

Freezing Point Depression