Problem: An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d = 1.114 g/mL; ℳ = 62.07 g/mol) and water (d = 1.00 g/mL) at 20°C. The density of the mixture is 1.070 g/mL. Express the concentration of ethylene glycol as:(c) Molarity

FREE Expert Solution
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FREE Expert Solution

We're being asked to calculate the molarity of the ethylene glycol solution.

Recall molarity:

molarity (M)=moles soluteL solution


The mixture is made by mixing equal volumes of ethylene glycol and water → we can assume any volume:

Assuming: volume solution = 100 L

volume ethylene glycol = 50 L
volume water = 50 L

We're going to calculate the molarity of the solution using the following steps:

Step 1: Calculate moles of ethylene glycol (e.g.)
Step 2: Calculate the molarity of the solution

90% (10 ratings)
Problem Details

An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d = 1.114 g/mL; ℳ = 62.07 g/mol) and water (d = 1.00 g/mL) at 20°C. The density of the mixture is 1.070 g/mL. Express the concentration of ethylene glycol as:

(c) Molarity

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