Sign up for free to keep watching this solution

Solution: A 75.0-mL volume of 0.200 M NH 3 (Kb = 1.8 x 10-5) is titrat...

Question

A 75.0-mL volume of 0.200 M NH 3 (Kb = 1.8 x 10-5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 13.0-mL of HNO3.