Recall that the rate law only focuses on the reactant concentrations and has a general form of:
k = rate constant
A & B = reactants
x & y = reactant orders
Step 1. Calculate order with respect to NO:
x = order
3 raised to the 2nd power = 9
x = 2 → 2nd order with respect to NO
Step 2. Calculate order with respect to O2:
y = order
since the numerator and the denominator is raised to the same power, you can simplify the equation to:
0.4 raised to the power of 1 = 0.4
y = 1 → 1st order with respect to O2
Step 3. Calculate the value of the rate constant
Go back to the given data. You can use any experimental data to calculate for k, but let’s use the 1st data for this calculation:
[NO] = 1.00 x 1018
[O2] = 1.00 x 1018
rate = 2.00 x 1016
k = 2.0 x 10-38
2NO (g) + O2 (g) → 2NO2 (g)
was studied, and the following data were obtained where
What would be the initial rate for an experiment where [NO] 0 = 6.21x 1018 molecules/cm3 and [O2]0 = 7.36 x 1018 molecules/cm3?
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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition practice problems.