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Clausius-Clapeyron Equation

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Clausius-Clapeyron Equation	5 mins	0 completed	Learn Summary

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Intermolecular Forces and Physical Properties
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Solution: The ΔH°_f of gaseous dimethyl ether (CH₃OCH₃) is −185.4 kJ/mol; the vapor pressure is 1.00 atm at −23.7°C and 0.526 atm at −37.8°C. (b) Calculate ΔH°_f of liquid dimethyl ether.

Solution: The ΔH°f of gaseous dimethyl ether (CH3OCH3) is −185.4 kJ/mol; the vapor pressure is 1.00 atm at −23.7°C and 0.526 atm at −37.8°C. (b) Calculate ΔH°f of liquid dimethyl ether.

Problem

The ΔH°_f of gaseous dimethyl ether (CH₃OCH₃) is −185.4 kJ/mol; the vapor pressure is 1.00 atm at −23.7°C and 0.526 atm at −37.8°C. (b) Calculate ΔH°_f of liquid dimethyl ether.

Clausius-Clapeyron Equation

Solution: The ΔH°f of gaseous dimethyl ether (CH3OCH3) is −185.4 kJ/mol; the vapor pressure is 1.00 atm at −23.7°C and 0.526 atm at −37.8°C. (b) Calculate ΔH°f of liquid dimethyl ether.

Solution: The ΔH°f of gaseous dimethyl ether (CH3OCH3) is −185.4 kJ/mol; the vapor pressure is 1.00 atm at −23.7°C and 0.526 atm at −37.8°C. (b) Calculate ΔH°f of liquid dimethyl ether.

Problem

Practice Problems

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Solution: The ΔH°_f of gaseous dimethyl ether (CH₃OCH₃) is −185.4 kJ/mol; the vapor pressure is 1.00 atm at −23.7°C and 0.526 atm at −37.8°C. (b) Calculate ΔH°_f of liquid dimethyl ether.