Problem: Diethyl ether has a ΔH°vap of 29.1 kJ/mol and a vapor pressure of 0.703 atm at 25.0°C. What is its vapor pressure at 95.0°C?

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FREE Expert Solution

ln P2P1=-HvapR[1T2-1T1]


Convert kJ/mol to J/mol:


Hvap=29.1 kJmol×103 J1 kJ

ΔHvap = 29100 J/mol



Solving for P2:

T1 = 25.0°C + 273.15 = 298.15  K

T2 = 95.0°C + 273.15 = 368.15 K

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Problem Details

Diethyl ether has a ΔH°vap of 29.1 kJ/mol and a vapor pressure of 0.703 atm at 25.0°C. What is its vapor pressure at 95.0°C?