Problem: What are the mole fractions of HNO3 and water in a concentrated solution of nitric acid (68.0% HNO3 by mass)?(a) Outline the steps necessary to answer the question.(b) Answer the question.

FREE Expert Solution

Assume 100 g total mass → get mass each → convert each to moles → Calculate molar mass. 


Assume 100 g total mass and  get mass each

% HNO3=mass HNO3total mass×100mass HNO3 = total mass(% HNO3100)mass HNO3 =100 g(68100)

mass HNO= 68 g


mass H2O = mass total - mass HNO3

mass H2O = 100 g - 68 g

mass H2O = 32 g


convert each to moles 

Molar mass H2O = 18.02 g/mol

32 g H2O ×1 mol H2O18.02 g H2O  = 1.776 mol H2O


Molar mass HNO3 = 63.02 g/mol

32 g HNO3 ×1 mol HNO363.02 g HNO3  = 0.508 mol HNO3


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Problem Details

What are the mole fractions of HNOand water in a concentrated solution of nitric acid (68.0% HNOby mass)?

(a) Outline the steps necessary to answer the question.

(b) Answer the question.

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