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Mole Fraction

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Sections
Solutions, Molarity and Intermolecular Forces	7 mins	0 completed	Learn
Henry's Law	20 mins	0 completed	Learn Summary
Calculate Molarity	27 mins	0 completed	Learn Summary
Mass Percent	10 mins	0 completed	Learn
Molality	15 mins	0 completed	Learn
Mole Fraction	14 mins	0 completed	Learn
The Colligative Properties	45 mins	0 completed	Learn

Additional Practice
Making Solutions
Freezing Point Depression
Colloid

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ppm
The Freezing Point Depression
Boiling Point Elevation

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Next SectionThe Colligative Properties

Solution: Calculate the molarity and mole fraction of acetone in a 1.00 m solution of acetone (CH₃COCH₃) in ethanol (C ₂H₅OH). (Density of acetone = 0.788 g/cm 3; density of ethanol = 0.789 g/cm3.) Assume that the volumes of acetone and ethanol add.

Solution: Calculate the molarity and mole fraction of acetone in a 1.00 m solution of acetone (CH3COCH3) in ethanol (C 2H5OH). (Density of acetone = 0.788 g/cm 3; density of ethanol = 0.789 g/cm3.) Assume that

Problem

Calculate the molarity and mole fraction of acetone in a 1.00 m solution of acetone (CH₃COCH₃) in ethanol (C ₂H₅OH). (Density of acetone = 0.788 g/cm ³; density of ethanol = 0.789 g/cm³.) Assume that the volumes of acetone and ethanol add.

Mole Fraction

Solution: Calculate the molarity and mole fraction of acetone in a 1.00 m solution of acetone (CH3COCH3) in ethanol (C 2H5OH). (Density of acetone = 0.788 g/cm 3; density of ethanol = 0.789 g/cm3.) Assume that the volumes of acetone and ethanol add.

Solution: Calculate the molarity and mole fraction of acetone in a 1.00 m solution of acetone (CH3COCH3) in ethanol (C 2H5OH). (Density of acetone = 0.788 g/cm 3; density of ethanol = 0.789 g/cm3.) Assume that

Problem

Practice Problems

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Solution: Calculate the molarity and mole fraction of acetone in a 1.00 m solution of acetone (CH₃COCH₃) in ethanol (C ₂H₅OH). (Density of acetone = 0.788 g/cm 3; density of ethanol = 0.789 g/cm3.) Assume that the volumes of acetone and ethanol add.