Step 1

$\overline{){\mathbf{molality}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{mol}\mathbf{}\mathbf{solute}}{\mathbf{kg}\mathbf{}\mathbf{solvent}}}\phantom{\rule{0ex}{0ex}}\mathbf{molality}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{27}\mathbf{.}\mathbf{0}\mathbf{}\overline{)\mathbf{g}\mathbf{}\mathbf{urea}}\mathbf{}\mathbf{\times}{\displaystyle \frac{\mathbf{1}\mathbf{}\mathbf{mol}\mathbf{}\mathbf{urea}}{\mathbf{60}\mathbf{.}\mathbf{06}\overline{)\mathbf{}\mathbf{g}\mathbf{}\mathbf{urea}}}}}{\mathbf{150}\mathbf{}\overline{)\mathbf{g}}\mathbf{}\mathbf{water}\mathbf{}\mathbf{\times}{\displaystyle \frac{\mathbf{1}\mathbf{}\mathbf{kg}}{{\mathbf{10}}^{\mathbf{3}}\mathbf{}\overline{)\mathbf{g}}}}}$

**molality = 2.997 mol/kg**

A solution is prepared by dissolving 27.0 g urea, (NH_{2})_{2}CO, in 150.0 g water. Calculate the boiling point of the solution. Urea is a nonelectrolyte.

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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition practice problems.