🤓 Based on our data, we think this question is relevant for Professor Coarfa's class at SJCD.

$\overline{){\mathbf{m}}{\mathbf{a}}{\mathbf{s}}{\mathbf{s}}{\mathbf{}}{\mathbf{p}}{\mathbf{e}}{\mathbf{r}}{\mathbf{c}}{\mathbf{e}}{\mathbf{n}}{\mathbf{t}}{\mathbf{}}{\mathbf{=}}\frac{\mathbf{m}\mathbf{a}\mathbf{s}\mathbf{s}\mathbf{}\mathbf{s}\mathbf{o}\mathbf{l}\mathbf{u}\mathbf{t}\mathbf{e}}{\mathbf{m}\mathbf{a}\mathbf{s}\mathbf{s}\mathbf{}\mathbf{s}\mathbf{o}\mathbf{l}\mathbf{u}\mathbf{t}\mathbf{i}\mathbf{o}\mathbf{n}}{\mathbf{\times}}{\mathbf{100}}}$

**mass H _{2} = 0.94 g**mass solution = mass H

mass solution = 0.94 g + 215 g

**mass solution = 215.94 g**

Solutions of hydrogen in palladium may be formed by exposing Pd metal to H_{2 }gas. The concentration of hydrogen in the palladium depends on the pressure of H_{2} gas applied, but in a more complex fashion than can be described by Henry’s law. Under certain conditions, 0.94 g of hydrogen gas is dissolved in 215 g of palladium metal (solution density = 10.8 g cm^{3}).

(c) Determine the percent by mass of hydrogen atoms in this solution.

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