# Problem: Calculate the solubility of O2 in water at a partial pressure of O2 of 120 torr at 25°C. The Henry’s law constant for O2 is 1.3 x 10-3 mol/L • atm for Henry’s law in the form C = kP, where C is the gas concentration (mol/L).

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###### FREE Expert Solution

$\overline{){{\mathbf{S}}}_{{\mathbf{gas}}}{\mathbf{=}}{{\mathbf{k}}}_{{\mathbf{H}}}{{\mathbf{P}}}_{{\mathbf{gas}}}}$

where Sgas = solubility of the gas (in mol/L or M), kH = Henry’s law constant for the gas, Pgas = partial pressure of the gas.

###### Problem Details

Calculate the solubility of O2 in water at a partial pressure of O2 of 120 torr at 25°C. The Henry’s law constant for O2 is 1.3 x 10-3 mol/L • atm for Henry’s law in the form = kP, where C is the gas concentration (mol/L).