The problem asks us to find which solution has a greater ion association using freezing point depression data. We can determine which has a greater ion association indirectly from the Van’t Hoff factor The Van’t Hoff factor is the number of ions created once the compound dissociates. A higher Van't Hoff factor means greater dissociation and lesser association. Inversely, a lower Van't Hoff factor means greater ion association.
The freezing point depression equation is:
The freezing-point depression of a 0.091-m solution of CsCl is 0.320˚C. The freezing-point depression of a 0.091-m solution of CaCl2 is 0.440˚C. In which solution does ion association appear to be greater? Explain.
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What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Freezing Point Depression concept. If you need more Freezing Point Depression practice, you can also practice Freezing Point Depression practice problems.
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Based on our data, we think this problem is relevant for Professor Yang's class at UT.
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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition practice problems.