Problem: A solution is prepared by mixing 50.0 mL toluene (C6H5CH3, d = 0.867 g/cm3) with 125 mL benzene (C6H6, d = 0.874 g/cm3). Assuming that the volumes add on mixing, calculate the mass percent, mole fraction, molality, and molarity of the toluene.

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FREE Expert Solution

Part A. Percent mass.

50.0 mL toluene (C6H5CH3, d = 0.867 g/cm3)

50.0 mL×1 cm31 mL×0.867 gcm3=43.35 g

125 mL benzene (C6H6, d = 0.874 g/cm3)

125 mL×1 cm31 mL×0.847 gcm3=105.875 g

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Problem Details

A solution is prepared by mixing 50.0 mL toluene (C6H5CH3, d = 0.867 g/cm3) with 125 mL benzene (C6H6, d = 0.874 g/cm3). Assuming that the volumes add on mixing, calculate the mass percent, mole fraction, molality, and molarity of the toluene.