Ch.12 - SolutionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: In lab you need to prepare at least 100 mL of each of the following solutions. Explain how you would proceed using the given information. d. 0.10 mole fraction of C6H12O6 in water (d = 1.00 g/cm3)

Solution: In lab you need to prepare at least 100 mL of each of the following solutions. Explain how you would proceed using the given information. d. 0.10 mole fraction of C6H12O6 in water (d = 1.00 g/cm3)

Problem

In lab you need to prepare at least 100 mL of each of the following solutions. Explain how you would proceed using the given information. 

d. 0.10 mole fraction of C6H12O6 in water (d = 1.00 g/cm3)

Solution
  • Recall that mole fraction is equal to:

  • Total moles of solution is equal to the moles of water and moles of glucose

Moles of solution = moles water + moles glucose

  • We can get the the moles of C6H12O6 , eventually the mass, using the provided volume of solution
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