Problem: Chloral, Cl3C—CH=O, reacts with water to form the sedative and hypnotic agent chloral hydrate, Cl3C—CH(OH)2. Draw Lewis structures for these substances, and describe the change in molecular shape, if any, that occurs around each of the carbon atoms during the reaction.

🤓 Based on our data, we think this question is relevant for Professor Pomeroy's class at UCSD.

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Cl3C-CH=O + H2O Cl3C-CH(OH)2


Cl3C-CH=O

Total valence e- = 36 e-


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Problem Details

Chloral, Cl3C—CH=O, reacts with water to form the sedative and hypnotic agent chloral hydrate, Cl3C—CH(OH)2. Draw Lewis structures for these substances, and describe the change in molecular shape, if any, that occurs around each of the carbon atoms during the reaction.

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Our tutors have indicated that to solve this problem you will need to apply the Molecular vs Electron Geometry concept. You can view video lessons to learn Molecular vs Electron Geometry. Or if you need more Molecular vs Electron Geometry practice, you can also practice Molecular vs Electron Geometry practice problems.

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Based on our data, we think this problem is relevant for Professor Pomeroy's class at UCSD.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.