For the equilibrium between the cis and trans isomers of CHF=CHF
cis-CHF=CHF ⇌ trans-CHF=CHF
which of the following statements is true:
a) If [trans] >> [cis] then Kc >> 1
b) If [cis] = [trans] then Kc = ∞
c) If [cis] >> [trans] then Kc >> 1
d) If [trans] = [cis] then Kc = 0
e) If [trans]>>[cis] then Kc << 1
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