Problem: Draw Lewis structures of all the important resonance forms of (b) HBrO4 (HOBrO3)

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FREE Expert Solution
  • For the Lewis structure of HBrO4, Br appears to have 7 valence electron, H as 1 and O has 6. Total valence electrons is 32. ((1(1) + 6(4) + 7(1)  = 32)
  • Br will appear as central atom since its less electronegative than O (H can't be central atom)
  • Draw the initial structure of HBrOwhere all O atoms is attached to Br and H on one of the O atom. This structure will try follow the octet rule to complete 8 electrons around each atom except for Br which has an expanded octet
  • Os around Br (except the OH) will try to have 1 electron (3 lone pairs in total) to complete the octet while Br will also take another electron forming 2 lone pairs
  • Calculating for the formal charges:

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Problem Details

Draw Lewis structures of all the important resonance forms of 

(b) HBrO4 (HOBrO3)