Problem: The gold foil Rutherford used in his scattering experiment had a thickness of approximately 6.0×10−3 mm .If a single gold atom has a diameter of 2.9×10-8 cm, how many atoms thick was Rutherford's foil?

🤓 Based on our data, we think this question is relevant for Professor Billman's class at Abilene Christian University.

FREE Expert Solution

We have to determine how many gold atoms thick was the gold foil used in Rutherford’s gold foil experiment.


To determine the thickness of gold foil in number of atoms, we can use the dimensional analysis.

We will first convert the thickness of foil from mm units to cm unitsso that the units can cancel out when we determine the number of gold atoms.

View Complete Written Solution
Problem Details

The gold foil Rutherford used in his scattering experiment had a thickness of approximately 6.0×10−3 mm .

If a single gold atom has a diameter of 2.9×10-8 cm, how many atoms thick was Rutherford's foil?