Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: In water, the equilibrium 2H2O(l) ⇌ H3O+ (aq) + OH−(aq)      Kc = 10−14 determines the concentrations of H3O+(aq) and OH -(aq). If the pH is 9.2, what is the OH - concentration? (note H3O+(aq) and H

Problem

In water, the equilibrium

2H2O(l) ⇌ H3O+ (aq) + OH(aq)      Kc = 10−14

determines the concentrations of H3O+(aq) and OH -(aq). If the pH is 9.2, what is the OH - concentration? (note H3O+(aq) and H+(aq) are equivalent ways of representing a solvated proton and pH = -log[H+(aq)].)

a) 9.76x10−6

b) 2.31x10−5

c) 3.88x10−4

d) 1.58x10−5

e) 2.54x10−6