Chemistry Isotopes Solution: Naturally occurring boron consists of two isotopes...

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Solution: Naturally occurring boron consists of two isotopes: 10B (19.9%) with an isotopic mass of 10.0129 amu and 11B (80.1%) with an isotopic mass of 11.00931 amu.What is the atomic weight of boron? Check your answer by looking at a periodic table.

Problem

Naturally occurring boron consists of two isotopes: 10B (19.9%) with an isotopic mass of 10.0129 amu and 11B (80.1%) with an isotopic mass of 11.00931 amu.

What is the atomic weight of boron? Check your answer by looking at a periodic table.

Solution

We are asked to determine the atomic weight (average molecular mass) of a Boron (B) given 10B (19.9%) with an isotopic mass of 10.0129 amu and 11B (80.1%) with an isotopic mass of 11.00931 amu.


We will solve for Boron's average mass using their abundance. 

The formula for average mass is:

Average molecular mass = (Mass isotope × Fractional Abundance)

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