Problem: The gold foil that Rutherford used in his scattering experiment had a thickness of approximately 0.006 mm .If a single gold atom has a diameter of 2.9 10-10 m, how many atoms thick was Rutherfords foil?

FREE Expert Solution
  • We can calculate for how many atoms thick the foil is by dividing the thickness of gold foil by the diameter of a gold atom
  • Setup a dimensional analysis with proper length conversion to determine the # of atoms
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Problem Details

The gold foil that Rutherford used in his scattering experiment had a thickness of approximately 0.006 mm .

If a single gold atom has a diameter of 2.9 10-10 m, how many atoms thick was Rutherfords foil?

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