We’re being asked to determine the **value of the copper in the coin** assuming that its thickness is uniform.

A coin is cylindrical in shape. So, we can use the formula for the volume of a cylinder.

The **volume of a cylinder** is given by the following equation:

$\overline{){\mathbf{Volume}}{\mathbf{}}{\mathbf{\left(}}{\mathbf{V}}{\mathbf{\right)}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}{{\mathbf{\pi r}}}^{{\mathbf{2}}}{\mathbf{h}}}$

where r = radius and h = height or thickness

**Density**, on the other hand, is given by the following equation:

$\overline{){\mathbf{Density}}{\mathbf{}}{\mathbf{\left(}}{\mathbf{d}}{\mathbf{\right)}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{mass}}{\mathbf{volume}}}$

*We will do the following steps to solve the problem:*

*Step 1: Calculate the volume of the coin*

*Step 2: Calculate the mass of the coin*

*Step 3: Calculate the value of the coin*

A U.S. 1-cent coin (a penny) has a diameter of 19 mm and a thickness of 1.5 mm. Assume the coin is made of pure copper,
whose density and approximate market price are 8.9 g/cm^{3} and $2.55 per pound, respectively.

Calculate the value of the copper in the coin, assuming its thickness is uniform.