Kinetic energy:

$\mathbf{KE}\mathbf{=}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{mv}}^{\mathbf{2}}$

v_{1} = 95 mi/h

v_{2} = 67.2 mi/h

mass remains the same: compare the factor v^{2} in the equation:

A baseball weighs 5.13 oz. What is the kinetic energy, in joules, of this baseball when it is thrown by a major league pitcher at 95.0 mi/ h?

**By what factor will the kinetic energy change if the speed of the baseball is decreased to 67.2 mi/h?**

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