Fill in the gaps in the following table, assuming ...

Question

Fill in the gaps in the following table, assuming each column represents a neutral atom:Symbol79BrProtons2582Neutrons3064Electrons4886Mass no.222207Complete the third row of the table.

Jules Bruno · Accepted Answer

We are asked to fill up the third row of the table below:Symbol79BrProtons2582Neutrons3064Electrons4886Mass no.2222071st column Given: 79Br mass no = 79For 79Br :Atomic number of Br = no of protons= no of electrons (neutral atom) = 35[readmore]Mass # = # of neutrons + # of protons   # of neutrons= Mass # - # of protons # of neutrons = 79 - 35 # of neutrons = 442nd columnGiven: Protons = 25 Neutrons  = 30Since Atomic No = No of protons. Looking at the periodic table,Atomic no 25 = ManganeseNo of protons = No of electrons  = 25Mass # = # of neutrons + # of protons   Mass # =30 + 25 Mass # = 55 The element is 55Mn.3rd columnGiven: No of neutrons = 64 No of electrons = 48Since Atomic no = no of protons = no of electrons (neutral atom) = 48Looking at the periodic table, Atomic No 48 = CadmiumMass # = # of neutrons + # of protons   Mass # = 64 + 48 Mass # = 112 The element is 112Cd.4th columnGiven: Mass no = 222No of Electrons: 86Atomic No = No of protons = no of electrons (neutral atom) = 86Looking at the periodic table, Atomic No = 86 = RadonMass # = # of neutrons + # of protons   # of neutrons= Mass # - # of protons# of neutrons = 222-86 # of neutrons = 136 The element is 222Rn. 5th columnGiven: No of protons = 82 Mass no = 207Atomic no = no of protons = no of electrons (neutral atom) = 82Looking at the periodic table, Atomic No =  82 = LeadMass # = # of neutrons + # of protons   # of neutrons= Mass # - # of protons # of neutrons = 207 - 82 # of neutrons = 125 The element is 207Pb. Symbol79Br55Mn112Cd222Rn207PbProtons3525488682Neutrons443064136125Electrons3525488682Mass no.7955112222207These are the values for the third row (neutrons).

Problem: Fill in the gaps in the following table, assuming each column represents a neutral atom:Symbol79BrProtons2582Neutrons3064Electrons4886Mass no.222207Complete the third row of the table.

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Problem Details

Symbol	⁷⁹Br
Protons		25			82
Neutrons		30	64
Electrons			48	86
Mass no.				222	207

Problem: Fill in the gaps in the following table, assuming each column represents a neutral atom:Symbol79BrProtons2582Neutrons3064Electrons4886Mass no.222207Complete the third row of the table.

FREE Expert Solution

Problem Details

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