🤓 Based on our data, we think this question is relevant for Professor Davis' class at UCF.
We have to determine the number of gold atoms in a gold cube with sides equal to 1.00 cm and the mass of 19.3 g.
The number of atoms in the given mass of an element can be determined by this formula:
NA = Avogadro’s number = 6.022×1023 atoms/mol
A cube of gold that is 1.00 cm on a side has a mass of 19.3 g. A single gold atom has a mass of 197.0 amu.
How many gold atoms are in the cube?
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Based on our data, we think this problem is relevant for Professor Davis' class at UCF.