Problem: Two students determine the percentage of lead in a sample as a laboratory exercise. The true percentage is 22.52%. The students results for three determinations are as follows:1. 22.52, 22.48, 22.542. 22.64, 22.58, 22.62Calculate the average value of the absolute deviations of each measurement from the average for the second set.

FREE Expert Solution

Step 1

absolute deviation = | true value - experimental value|

(1) absolute deviation = |22.52 - 22.64| = 0.12

(2) absolute deviation = |22.52 - 22.58| = 0.06

(3) absolute deviation = |22.52 - 22.62| = 0.1

Step 2

$\mathbf{average}\mathbf{ }\mathbf{=}\mathbf{ }\frac{\mathbf{sum}\mathbf{ }\mathbf{of}\mathbf{ }\mathbf{the}\mathbf{ }\mathbf{measurement}}{\mathbf{number}\mathbf{ }\mathbf{of}\mathbf{ }\mathbf{measurement}}$

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