Problem: The concentration of carbon monoxide in an urban apartment is 48 g/m3. What mass of carbon monoxide in grams is present in a room measuring 12.0 imes ; 12.5 imes ; 21.5  ft?

FREE Expert Solution

Volume = height x weight x length

Volume = 12.0 ft x 12.5 ft x 21.5 ft

Volume = 3225 ft3


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Problem Details

The concentration of carbon monoxide in an urban apartment is 48 g/m3. What mass of carbon monoxide in grams is present in a room measuring 12.0 12.5 21.5  ft?

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