Ch.18 - ElectrochemistryWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Determine whether HI can dissolve each metal sample. If it can, write a balanced chemical reaction showing how the metal dissolves in HI and determine the minimum volume of 3.5 M HI required to completely dissolve the sample.a. 2.15 g Alb. 4.85 g Cuc. 2.42 g Ag

Solution: Determine whether HI can dissolve each metal sample. If it can, write a balanced chemical reaction showing how the metal dissolves in HI and determine the minimum volume of 3.5 M HI required to comple

Problem

Determine whether HI can dissolve each metal sample. If it can, write a balanced chemical reaction showing how the metal dissolves in HI and determine the minimum volume of 3.5 M HI required to completely dissolve the sample.

a. 2.15 g Al

b. 4.85 g Cu

c. 2.42 g Ag

Solution

We’re being asked to determine whether HI can dissolve the given metal sample, write a balanced reaction, and the volume of 3.5 M HI required to completely dissolve the sample.

We’re going to dissolve metals meaning the metals will undergo oxidation. HI will break up in the solution:

Recall:

Lose               Gain
Electron         Electron
Oxidation       Reduction


• HI(aq) → H+(aq) + I-(aq)

▪ if we’re going to oxidize the metals, it means that something is also reduced in the solution
▪ I-(aq) → with negative charge and it is the most reduced form of I X

H+(aq) → has a positive charge → can gain e- and can be reduced ü

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