We’re being asked to determine the cathode and anode half-reactions for the electrolysis of an aqueous CuBr2 solution.
Recall that the cathode is where reduction occurs while the anode is where oxidation occurs.
Since CuBr2 is an ionic compound, it forms ions when dissociating in water.
The dissociation of CuBr2 in water is as follows:
The bromide ion, Br–, has a charge of –1. Copper then has a charge of +2:
CuBr2(s) → Cu2+(aq) + 2 Br–(aq)
Write equations for the half-reactions that occur at the anode and cathode for the electrolysis of each aqueous solution:
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Our tutors have indicated that to solve this problem you will need to apply the Electrolysis of Water & Mixture of Ions concept. If you need more Electrolysis of Water & Mixture of Ions practice, you can also practice Electrolysis of Water & Mixture of Ions practice problems.
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Our data indicates that this problem or a close variation was asked in Chemistry: A Molecular Approach - Tro 3rd Edition. You can also practice Chemistry: A Molecular Approach - Tro 3rd Edition practice problems.