We are asked to calculate the edge length of the cube?

Calculate volume:

$\mathbf{3}\mathbf{.}\mathbf{05}\mathbf{}\mathbf{x}\mathbf{}{\mathbf{10}}^{\mathbf{23}}\mathbf{}\overline{)\mathbf{atoms}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\overline{)\mathbf{mol}}}{\mathbf{6}\mathbf{.}\mathbf{022}\mathbf{\times}{\mathbf{10}}^{\mathbf{23}}\mathbf{}\overline{)\mathbf{atoms}}}\mathbf{\times}\frac{\mathbf{47}\mathbf{.}\mathbf{87}\overline{)\mathbf{}\mathbf{g}}}{\mathbf{1}\mathbf{}\overline{)\mathbf{mol}}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}{\mathbf{cm}}^{\mathbf{3}}}{\mathbf{4}\mathbf{.}\mathbf{50}\overline{)\mathbf{}\mathbf{g}}}$

**= 5.39 cm**^{3 }

A titanium cube contains 3.05 x 10^{23} atoms. The density of titanium is 4.50 g/cm^{3}

What is the edge length of the cube?

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